This circuit needs maximum 5v - 7v if powered directly through DC power supply only. If ur supplying AC current,

you need to have a transformer that outputs 12v ac current to it. You also need to add a 5v potentiometer to it ,to control the voltage. (if u don't have it, u can fix a 1k resistor to it.)

once u solder the components to the circuit, simply upload the code to the arduino pro.(Do not solder the arduino pro directly to the PCB. u can use female pin headers and fix it.) . make sure to put ur remote's decode results to the code.

these are the components,

• arduino pro mini (5v)
• 5v relay
• 3 pin screw header
• 2 pin screw header
• LM317
• 5k potentiometer or 1k resistor
• 2200 uF capacitor
• 100uF capacitor
• 2N3904 transistor
• LED'S (2)
• VS1838 IR receiver
• 1n4007 diode (4)
• 1k resistor (2)
• 220 ohm resistor(2)
• 10k resistor
• 0.33uF ceramic capacitor
• dip switch

for more info about this circuit, check out my project in instructables.

https://www.instructables.com/id/ARDUINO-IR-REMOTE-CONTROLLED-RELAY/

hope u enjoyed this project. plese like :)

if u have any questions, u are welcomed to ask in the comment section :)

#include <IRremote.h>


int RECV_PIN = 3;
int RELAY_PIN2 = 8;

IRrecv irrecv(RECV_PIN);
decode_results results;

void dump(decode_results *results) {
  int count = results->rawlen;
 
}

void setup()
{
  pinMode(RELAY_PIN, OUTPUT);
  pinMode(13, OUTPUT);
  digitalWrite(13,LOW);
    Serial.begin(9600);
  irrecv.enableIRIn(); // Start the receiver
}

int on = 0;
unsigned long last = millis();

#define BUTTON_1 0xFF30CF  //make sure u put ur decoded results here!





void loop() {
  if (irrecv.decode(&results)) {
  
    if (results.value == BUTTON_1)
    {
    
      on = !on;
      digitalWrite(RELAY_PIN2, on ? HIGH : LOW);
      digitalWrite(13, on ? HIGH : LOW);
      dump(&results);
    }

else{
  digitalWrite(13,LOW);
}
}